Sun September 06, 2009 By: Khushal Gupta


Expert Reply
Wed September 09, 2009

Let A , B and C be the vertices of triangle ABC with coordinates (x1,y1)  (x2,y2),(x3,y3) respectively.
P be any general point  with coordinates (x,y).Coordinates of Centroid will be ( (x1+x2+x3)/3 ,(y1+y2+y3)/3) 

Apply distance formula to get  PA2  PB2PC2 GA2 GB2GCand GP2 

For example

PA2 = (x-x1)2 + (y-y1)2

PB2 = (x-x2)2 + (y-y2)2

PC2 =  (x-x3)2 + (y-y3)2  

Similarly find GA2 GB2GCand GP2  substitute the values and simplify.

Incaseyou are getting stuck do let us know.

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