Question
Wed February 02, 2011 By: Ananya Vyas
 

consider 3 boxes held together. The 1st box is of mass 4 kg , the 2nd box is of mass 8 kg, and the third box is of mass 12 kg. If a force of 6N is exerted on the 1st box, then what is acceleration produced in all the 3 boxes individually and the force acted upon them individually?

Expert Reply
Wed February 02, 2011
Dear student,
 
Since the total mass in motion is 14 kg, and the force applied is 6N, the acceleration of the masses is F/m = 6/14 = 0.43m/s^2
 
If 8 kg mass is moving with acceleration , thne the force acting on it will be:
 
f= ma
f =8X0.43 = 3.44m/s^2
 
If 12 kg mass is moving with acceleration , thne the force acting on it will be:
f=12X0.43 =5.16m/s^2
 
Hope this helps.
Thanking you
Team
Topperelarning.com
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