Question
Fri May 30, 2008 By:

In the figure O is the centre then angle BTC is equal to?

Angle BTC ? outside the circle

Expert Reply
Sat July 26, 2008

the angle OCA = 23 degrees   [  [ OC is perpendiculat to the tangent CT  , so OCT =   and the adjacent  angle let us takeOCX 

    therefore  OCA = 90 - 67 = 23

   OCA = OAC  = 23 ,[  isoceles  triangle  OCA ]

    the external angle =  the sum of the internal

    67  =  23  + ATC  ===>  ATC = 67 - 23  = 44

 therefore   angle  ATC  == 44 degrees

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