Question
Mon May 21, 2012 By: Divyadutta Behura

a wire of resistance 20 ohm is drawn out so that its length is increased twice its original length.determine its new resistance?

Expert Reply
Tue May 22, 2012
Length got doubled 
 
pi (r12) l1 = pi (r22) l2
 
(r12) /  (r22) = 2
 
(r22) = (r12) /2
 
So resiatnace will be 4 times & it will be 20 * 4 = 80 ohms
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