Question
Wed April 16, 2014 By: Yash Sahu

3 moles of an ideal gas occupies 100L under certain conditions .1.5 moles of the gas is removed and the temperature of the gas is doubled keeping the pressure constant . what is the new volume of the gas?

(A)50L

(B)200L

(C)400L

(D)100L

Expert Reply
Thu April 17, 2014
PV = nRT
P1V1= n1RT1
P2V2 = n2RT2
P1= P2= P
P = n1RT1 / V1 and P = n2RT2 / V2
T2= 2 T1, V1= 100 L,  n1= 3 moles and n2 = 1.5 moles
n1T1 / V1 = n2 x 2T1 / V2
3/100  =  1.5 x 2 / V2
V2 = 1.5 x 2 x 100 / 3
V2 = 100 L
 
The new volume is 100 L.
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