Question
Fri March 01, 2013 By: Renu Mariam John
 

3 capacitors of capacitances in the ratio 1:2:3 are connected in parallel .their effective capacitance in parallel is greater than that in series by 60/11 pF.calculate the individual capacitances.

Expert Reply
Mon March 04, 2013
(C+2C+3C)-6C/11  =60/11
C=1
so the indiv cap are:1pF,2pF and 3 pF
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