Question
Tue April 22, 2014 By: Ram Kumar

1)   2)   3)   4)     

Expert Reply
Wed April 23, 2014

Aqueous KOH results into substitution reaction.

Cl3C−CH2−CH3+3KOH(aq)→(OH)3C−CH2−CH3+3KCl

It may be noted that more than one OH group cannot be present on the same carbon atom. In such a case, the compound will be extremely unstable and will readily lose a water molecule to form more stable propionic acid.

(OH)3C−CH2−CH3?HOOC−CH2−CH3+H2O

Thus, propionic acid is the major product along with water molecule.

Hence, the corrrect option is propionic acid (option 2).

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