Question
Sat February 23, 2013 By:
 

0.12g of an organic compound containing phosphorous gave 0.22g of Mg2P2O7 by usual analysis. calculate the percentage of phosphorous in the compound.

Expert Reply
Sun February 24, 2013
The mass of the compd = 0.12 g
Mass of Mg2P2O7     = 0.22 g
Since 1 mole of Mg2P2O7 has 2 g atoms of P, or
222 g of Mg2P2O7 = 62 g of P
 
So, 0.22 g of Mg2P2O7 contains P =  62/222  x 0.22  g 
So % P present in the compound = 62/222 x  0.22 x 100/ 0.12 

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