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B is present on corners and face centres with number of B atoms on face centres along one of the axis are removed.
A is present on body centre and edge centres.
Number of B atoms = 8 x (1/8) + 4 x (1/2) = 3
Number of A atoms = 12 x (1/4) + 1 = 4
Formula of the compound = A4B3
Answer is C