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ye solve krna h sir

Asked by navodayjahajiya3009 | 02 May, 2019, 11:54: AM

Expert Answer

Let the resultant charge on a hydrogen be

open parentheses e plus increment e close parentheses minus e equals increment e

Therefore the electrostatic force of attraction betweem the atoms will be

fraction numerator K q subscript 1 q subscript 2 over denominator d squared end fraction equals fraction numerator begin display style 9 cross times 10 to the power of 9 increment e cross times increment e end style over denominator begin display style d squared end style end fraction equals fraction numerator begin display style 9 cross times 10 to the power of 9 open parentheses increment e close parentheses squared end style over denominator begin display style d squared end style end fraction

The gravitational force of attraction between the two hydrogen atom will be

fraction numerator G m subscript H cross times m subscript H over denominator d squared end fraction equals fraction numerator 6.67 cross times 10 to the power of negative 11 end exponent cross times 1.67 cross times 10 to the power of negative 27 end exponent cross times 1.67 cross times 10 to the power of negative 27 end exponent over denominator d squared end fraction

As given in the question Gravitational force of attraction is equal to Electrostatic force of repulsion

Therefore,

fraction numerator 6.67 cross times 10 to the power of negative 11 end exponent cross times 1.67 cross times 10 to the power of negative 27 end exponent cross times 1.67 cross times 10 to the power of negative 27 end exponent over denominator d squared end fraction equals fraction numerator 9 cross times 10 to the power of 9 open parentheses increment e close parentheses squared over denominator d squared end fraction open parentheses increment e close parentheses squared equals fraction numerator 6.67 cross times 10 to the power of negative 11 end exponent cross times 1.67 cross times 10 to the power of negative 27 end exponent cross times 1.67 cross times 10 to the power of negative 27 end exponent over denominator 9 cross times 10 to the power of 9 end fraction open parentheses increment e close parentheses squared equals fraction numerator 6.67 cross times 10 to the power of negative 11 end exponent cross times 1.67 cross times 10 to the power of negative 27 end exponent cross times 1.67 cross times 10 to the power of negative 27 end exponent over denominator 9 cross times 10 to the power of 9 end fraction increment e equals 1.437 cross times 10 to the power of negative 37 end exponent C

Answered by Utkarsh Lokhande | 02 May, 2019, 04:59: PM

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