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CBSE Class 12-science Answered

Write the principle of working of a potentiometer. Describe briefly, with the help of a circuit diagram, how a potentiometer is used to determine the internal resistance of a given cell.
Asked by Topperlearning User | 28 Apr, 2015, 10:48: AM
answered-by-expert Expert Answer

Principle of working: The voltage drop along the wire is directly proportional to the length of the wire. The potentiometer works without drawing any current from the voltage source.

We can also use a potentiometer to measure internal resistance of a cell. For this the cell (emf E) whose internal resistance (r) is to be determined is connected across a resistance box through a

Key K2, as shown in the figure.

With key K2 open, balance is obtained at length L1 (AN1).

Then,

E = ΦL1

When key K2 is closed, the cell sends a current (I ) through the resistance box (R). If V is the

terminal potential difference of the cell and balance is obtained at length L2 (AN2), then

V = ΦL2

So, we have E/V = L1/L2

But, E= I (r + R) and V = IR. This gives

E/V = (r + R)/R

On comparing the above equations, we get,

(R + r)/R = L1/L2

Using the above equation, we can find the internal resistance of a given cell.

Answered by | 28 Apr, 2015, 12:48: PM
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