NEET Class neet Answered
Work done when an object goes up on a rough inclined plane with explanation . How Frictional force is added up in this case??
Asked by vijaygireesh | 03 Apr, 2020, 09:56: PM
Expert Answer
figure shows the resistive forces acting on block of mass when it is pushed up on an inclined plane sureface by applied force F.
Force mgsinθ is the resolved component of weight mg that acts parallel to inclined surface and acts down ward as shown in figure.
when the block is pushed up, friction force is acting in the direction opposite to motion of block.
Friction force is μ×N , where μ is friction coefficient and N is normal force. Normal force equals mg cosθ.
Hence when the block is pushed up on the inclined force , work has to be peroformed
against the opposing forces ( mg sinθ ) and ( μ mg cosθ )
Since workdone is product of total opposing force and distance d moved on inclined plane surface,
we have workdone W is given as, W = [ mg sinθ + μ mg cosθ ] × d
Answered by Thiyagarajan K | 03 Apr, 2020, 11:07: PM
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