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CBSE Class 12-science Answered

Why the flux of electric field due to these charges through the surface S is zero??
Asked by ayushi | 26 Apr, 2016, 06:38: PM
answered-by-expert Expert Answer
If we apply Gauss' law to a closed surface, then it says that flux enclosed inside a surface is the ratio of total charge enclosed in it to ε0.
 
Now, the total charge enclosed in the surface is +q + (-q) = q - q = 0
 
Hence, the flux enclosed is zero.
Answered by Romal Bhansali | 27 Apr, 2016, 08:43: AM

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CBSE 12-science - Physics
13./A point charge of 12 µC is located at the centre of a cube of side 1 m. Calculate the electric flux through each face of the cube. (H.S.S.C.E.1999~S) [Ans. 2.26\times10^{5}N~m^{2}C^{-1}]
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what is si unit of electric flux
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Charge of 2C is placed at the centre of a cube of volume 8 cm^3. What is the electric flux passing through one face? 
Asked by hitanshu04 | 27 May, 2021, 07:33: PM
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The electric field components in are Ex = A+Bx, Ey = Ez = 0, in which A = 800 N/C , B= 100 N/C-m. Calculate  (a) the flux through the cube (b) the charge within the cube. Assume that a = 0.1 m
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Can we use the formula electric flux is equal to  E×A cos theta
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A point charge is placed at the centre of a closed Gaussian spherical  surface of radius r. Electric flux passing through the surface is Φ. How is  the electric flux Φ through the surface affected when the following  changes are made in turn: (i) The spherical surface is replaced by a cylindrical surface of the  same radius? (ii) The point charge is replaced by an electric dipole? Justify your  answer in each case. 
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