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Which term of the AP: 5, 15, 25, ..... will be 130 more than the 31st term?

Asked by Topperlearning User 22nd September 2017, 3:26 PM
Answered by Expert
Answer:

Here, a = 5 and d = 10

a31 = a + 30d = 5 + 30 10 = 305

Let the required term be the nth term. Then,

an= 130 + a31

a+(n - 1)d = 130 + 305

5+(n - 1)10 = 435

(n - 1)10 = 430

n - 1 = 43

n = 44

Hence, the 44th term of the given AP is 130 more than its 31st term.

Answered by Expert 22nd September 2017, 5:26 PM
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