CBSE Class 9 Answered
Which point on x-axis is equidistant from (7,6) and (-3,4) ?
Asked by Jai Khurana | 03 Aug, 2013, 01:00: PM
Expert Answer
Let the point on x-axis be P (x, 0).
The given points are A(7, 6) and B(3, 4).
Since, point P is equidistant from A and B, therefore AP = BP
or AP2 = BP2
(7 x)2 + (6 0)2 = (3 x)2 + (4 0)2
49 + x 2 14x + 36 = 9 + x 2 + 6x + 16
85 14x = 6x + 25
20x = 60
x = 3
Hence, the required point is (3, 0).
Answered by | 03 Aug, 2013, 04:01: PM
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