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Home / Doubts and Solutions/NEET/Chemistry

When x molecules are removed from 200mg of N2O 2.89×10-3 moles of N2O are left. Then x will be?

Asked by priyankachakraborty_759 10th June 2018, 11:16 AM
Answered by Expert
Answer:
Given colon Weight space of space space straight N subscript 2 straight O space equals space 200 space mg space space space space space space space space space space space space space space space space space space space space space space space space equals space 0.2 space straight g Moles space of space space straight N subscript 2 straight O space remained space equals 2.89 space cross times 10 to the power of negative 3 space end exponent mole Molecular space mass space of space straight N subscript 2 straight O space equals space 44 Moles space of space space straight N subscript 2 straight O space equals space fraction numerator 0.2 over denominator 44 end fraction space space space space space space space space space space space space space space space space space space space space space space equals space 4.55 space cross times 10 to the power of negative 3 end exponent space moles Moles space of space space straight N subscript 2 straight O space removed space equals space apostrophe straight x apostrophe Moles space of space space straight N subscript 2 straight O space remained space equals space 2.89 space cross times 10 to the power of negative 3 space end exponent mole therefore space 4.55 space cross times 10 to the power of negative 3 end exponent space minus space apostrophe straight x apostrophe space equals space 2.89 space cross times 10 to the power of negative 3 space end exponent space space space space space space space space space space space space space space space space space space space space space space space space space space space space space apostrophe straight x apostrophe space equals space space 4.55 space cross times 10 to the power of negative 3 end exponent minus 2.89 space cross times 10 to the power of negative 3 space end exponent Moles space of space space straight N subscript 2 straight O space remained equals space 1.65 cross times 10 to the power of negative 3 end exponent space mole As comma space 1 space mole space equals space 6.022 cross times 10 to the power of 23 space molecules 1.65 cross times 10 to the power of negative 3 end exponent space mole space equals space space 6.022 cross times 10 to the power of 23 cross times 1.65 cross times 10 to the power of negative 3 end exponent space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 9.97 space cross times 10 to the power of 20 space molecules space
 
9.97 ×1020 molecules are removed.
Answered by Expert 11th June 2018, 9:55 AM
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