CBSE Class 12-science Answered
When AABbCc is crossed with aaBbCc then the probality of genotype AaBbCc will be
Asked by Atulcaald | 29 Apr, 2018, 01:10: AM
Expert Answer
Parents : AABbCc × aaBbCc
Gametes : ABC, Abc, ABc, AbC aBC, aBc, abC, abc
Cross:
|
|
aBC |
aBc |
abC |
abc |
|
ABC |
AaBBCC |
AaBBCc |
AaBbCC |
AaBbCc |
|
Abc |
AaBbCc |
AaBbcc |
AabbCc |
Aabbcc |
|
ABc |
AaBBCc |
AaBBcc |
AaBbCc |
AaBbcc |
|
AbC |
AaBbCC |
AaBbCc |
AabbCC |
AabbCc |
The probability of genotype AaBbCc is 4 / 16 = 4 : 16. This means that out of every 16 progeny, 4 progeny will have the genotype AaBbCc.
Answered by Sheetal Kolte | 30 Apr, 2018, 07:12: PM
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