When a stone is falling from a mountain its initial velocity is 0 and acceleration due to gravity is 9.8m/s2.Velocity of stone is given by v = 9.8 t.Draw its graph and find the velocity of stone after 4 secs ?
The graph of 'v' vs 't' is a straight line passing through the origin with slope 9.8
The velocity after 4 secs can be found by substituting t=4 in the equation.
Hence, 'v' after 4 secs= 9.8X4= 39.2 m/s
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