CBSE Class 9 Answered
when a momentum of a body increases by 100 percent then its kinetic energy increases by ___________.
Asked by | 25 Dec, 2011, 12:00: AM
Expert Answer
p'=100% x p + p
=2p
K'=(p')2/2m
=4p2/2m=4K = 3K + K = 300% K + K
KE becomes four times. It means that the kinetic energy increases by 300%.
Answered by | 25 Dec, 2011, 11:50: PM
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