Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Study plan details

10:00 AM to 7:00 PM IST all days.

For Franchisee Enquiry

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

93219 24448 / 99871 78554

Mon to Sat - 10 AM to 7 PM

When a body slides down from rest along a smooth inclined plane of angle 45degree with horizontal , it takes T time. When same body slides down a rough inclined plane making same angle & through same distance, It is seens to be taken pT, where p is some number greater than 1. Calculate the coefficient of friction between body and rough plane.

Asked by Jojo 6th March 2016, 9:04 PM
Answered by Expert
Answer:

Hi,

Acceleration down the smooth inclined plane will be g sinθ and on the rough inclined plane will be (g sinθ - μ cosθ).

If the length of the inclined plane is l, then

l = 1/2 × (g sinθ) t2 and l = 1/2 × (g sinθ - μ cosθ) × (pt)2

Solving, we get

μ = tanθ (1 - 1/p2)

Answered by Expert 7th March 2016, 6:20 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Free related questions

Chat with us on WhatsApp