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When 229 J of energy is supplied as heat at constant pressure to 3 mol Ar(g), the temprature is incrased by 2.55 k . Calculate the molar heat capacity at constant volume    
Option
1)30 kJ k^-1mol^-1
2)30 J K^-1mol^-1
3)21.7 J K^-1mol^-1
4)21.7 kJ k^-1mol^-1
 
 Chapter thermodynamics

Asked by Sai 8th October 2017, 6:22 PM
Answered by Expert
Answer:
Cp-Cv = nR
Cp = q/ΔT
Cp = 229 J / 2.55 K  = 89.80 J K-1 
Cv = Cp - nR = 89.80 - (3 × 8.314) = 64.86 J K-1
Cv per mol = 64.86 / 3 = 21.6 J K-1 mol-1
 
 
Answered by Expert 10th October 2017, 4:24 PM
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