ICSE Class 9 Answered
What will be the magnification (positive/negative) in the following cases?
when the image is real and inverted, and when the image is virtual and erect.
Also give reason.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
Expert Answer
(a) When the image is real, it lies below the principal axis; hence height of image is negative as per New Cartesian sign convention. As height of object is always positive, therefore,
Magnification, m =
(b) When the image is virtual, it lies above the principal axis; hence height of image is positive as per New Cartesian sign convention. As height of object is always positive, therefore,
Magnification, m =
Answered by | 04 Jun, 2014, 03:23: PM
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