ICSE Class 10 Answered
What volume of oxygen at STP is required to affect combustion of 11 litres of Ethylene at 273 C and 380 mm of hg
Asked by Howisdone1 | 01 Feb, 2019, 03:52: PM
Expert Answer
Given:
P = 380 mmHg
= 0.5 atm
T = 273 °C
= 273+273
= 546 K
V = 11 litre
No. of moles = n
We have,
PV = nRT
The reaction is :
So for 1 mol of C2H4 combines with 3 mol of O2
Now 0.122 moles of C2 H4 will combine with 0.122×3
= 0.368 mol
Volume of 1 mole of gas is 22.4 litre
Volume of 0.368 mol = 22.4 × 0.368
= 8.24 litre
Volume of oxygen is 8.24 litre.
Answered by Varsha | 01 Feb, 2019, 06:30: PM
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