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what is the second ionisation potential in Ev of oxygen and flourine atoms resp. and how to calculate it?

Asked by vedant shah 20th June 2017, 9:15 AM
Answered by Expert

Second Ionisation energy for oxygen = 35.1 eV

Second Ionisation energy for fluorine = 34.99 eV

The second ionisation energy is the energy required to remove the electron from the corresponding mono-valent cation of the respective atom.

Oxygen has greater second ionisation energy than fluorine.

This is because oxygen atom has stable electronic configuration, 2s2 2p3 after removing one electron, the O+ shows greater ionisation energy than F+.

Answered by Expert 20th June 2017, 10:36 AM
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