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CBSE Class 9 Answered

WHAT IS THE REMAINDER WHEN 5Xcube-7Xsquare+3X+13 IS DIVIDED BE X/2+1
Asked by Keerthi | 08 Jun, 2017, 08:20: PM
answered-by-expert Expert Answer
begin mathsize 16px style By space remainder space theorem comma space required space remainder space is space equal space to space straight p open parentheses negative 2 close parentheses comma space space space space space open square brackets straight x over 2 plus 1 equals 0 rightwards double arrow straight x over 2 equals negative 1 rightwards double arrow straight x equals negative 2 close square brackets Now comma space straight p left parenthesis straight x right parenthesis equals 5 straight x cubed minus 7 straight x squared plus 3 straight x plus 13 rightwards double arrow straight p left parenthesis negative 2 right parenthesis equals 5 left parenthesis negative 2 right parenthesis cubed minus 7 left parenthesis negative 2 right parenthesis squared plus 3 left parenthesis negative 2 right parenthesis plus 13 space space space space space space space space space space space space space space space space equals 5 left parenthesis negative 8 right parenthesis minus 7 left parenthesis 4 right parenthesis minus 6 plus 13 space space space space space space space space space space space space space space space space space equals negative 40 minus 28 minus 6 plus 13 space space space space space space space space space space space space space space space space equals negative 61 Hence comma space required space remainder space is space minus 61. end style
Answered by Rashmi Khot | 09 Jun, 2017, 09:53: AM

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CBSE 9 - Maths
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