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What is the probability of having 53 Thursdays in a leap year?

Asked by Topperlearning User 4th April 2014, 10:52 AM
Answered by Expert
Answer:

In a leap year, there are 366 days.

52 weeks = 364 days

1 leap year = 52 weeks and 2 days

These extra two days can be sun-mon, mon-tue, tue-wed, wed-thu, thu-fir, fri-sat, sat-sun.

Total number of outcomes = 7

Number of favorable outcomes = 2

P(53 Thursdays) =

Answered by Expert 4th April 2014, 12:52 PM
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