what is the pressure inside a drop of mercury of radius 3milli metre at room temparature surface tension of mercury 4.65*10^-1 n/m
Asked by Shabnakp
12th January 2013,
10:46 PM
Answered by Expert
Answer:
excess pressure inside te drop=2S/R
pi-po=2S/R
P i=Po+2S/R
Putting the values of above quantities, the pressure inside the mercury drop can be found out.
Answered by Expert
13th January 2013,
12:46 AM
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