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what is the oxidation state of K in KO2?
 

Asked by rajenderdagar123 14th February 2017, 9:15 PM
Answered by Expert
Answer:
The oxidation state of each oxygen atom is -1/2 since it is a superoxide ion.
Let the oxidation state of K be x.
x + 2(-1/2) = 0
2x-2 = 0
2x=2
x=+1
Answered by Expert 15th February 2017, 11:31 AM
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