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What is the composition of the vapour which is in equilibrium at 30 degree celcius with a benzene-toluene solution with a mole fraction of benzene of 0.400? (P0 B is 119 torr and P0 T is 37 torr)       (a) 1.237  (b) 2.237  (c) 3.237  (d) 0.237

Asked by Balbir 28th July 2019, 7:59 PM
Answered by Expert
Answer:
Q. What is the composition of the toluene  vapour which is in equilibrium at 30 degree celcius with a benzene-toluene solution with a mole fraction of benzene of 0.400? (P0 B is 119 torr and P0 T is 37 torr)  

Given:
 
T = 30 °C
 
PB0 = 119 torr
PT0 = 37 torr
PT  = XT PT0 
Mole fraction of benzene = 0.4
 
Mole fraction of ttoluene = 1 - 0.4
 
= 0.6
 
According to Raoult's law,
 
PB = XBP0 
PT  = XT PT0 
 
Total pressue = PB + PT  ---(1)
 
By putting values in eq (1)
 
PTot = XBPB0 + XT PT0 
 
       = (0.4 × 119) +  (0.6×37)
 
       = 69.8  torr
 
Mole fraction of toluene in vapour phase
 
straight P subscript 0 space end subscript straight X subscript straight T equals straight X subscript straight T subscript vap straight P subscript straight T

straight X subscript straight T subscript vap space equals space fraction numerator straight P subscript 0 space end subscript straight X subscript straight T over denominator straight P subscript straight T end fraction

equals space fraction numerator 37 cross times 0.6 over denominator 69.8 end fraction

equals space 0.31 

 

Answered by Expert 28th July 2019, 11:57 PM
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