Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

Waterin a canal, 30 dm wide and 12 dm deep is flowing with the velocity of 10 km/hr. How much area will it irrigate in 30 minutes, if 8 cm of standing water is required for irrigation?

Asked by 26th January 2014, 7:08 AM
Answered by Expert
Answer:
Width of the water canal = 30 dm = 30 x 10 cm = 300 cm Depth of the canal = 12 dm = 12 x 10 cm = 120 cm Velocity of the water = 10 km/hv = (10 x 1000 x 100)/60 cm/minute That is velocity of the water = (100000/6) cm/minute Distance covered in 30 minutes = 30 x (100000/6) = 500000 cm Volume of water = 500000 x 300 x 120 = 18,00,00,00,000 cubic centimeter Area irrigated by this water if 8 cm standing water is desired = (500000 x 300 x 120 /8) sq cm = 2,25,00,00,000 sq cm = 2,25,000 sq m =0.225 sq km
Answered by Expert 29th January 2014, 4:37 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp