Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 11-science Answered

Water is flowing with a speed of 4 m/s in a horizontal pipe of non-uniform area of cross-section decreasing from 0.04 m² to 0.01 m² at pressure 40 x 104 Pa. What will be the pressure at narrower end?
Asked by Topperlearning User | 31 Jul, 2014, 03:30: PM
answered-by-expert Expert Answer

v1 = 4 m/s, a1 = 0.04 m², P1 = 40 x 104 Pa

a2 = 0.01 m², P2 = ?

According to equation of continuity, we have
a1v1 = a2v2

v= a1v1 / a2 = 0.04 x 4/ 0.01 = 16 m/s

According to Bernoulli's theorem, we have
P1+ ½ρv12 = P2 + ½ρv22
P2 = P1+ ½ρ(v12 - v22) = 40 x 104 + ½ x 10³ (4² - 16²)
    = 40 x 104  - ½ x 10³ x 240
    = (400 - 120) x 10³
    = 280 x 10³ Pa
Answered by | 31 Jul, 2014, 05:30: PM
CBSE 11-science - Physics
Asked by joelisaacsam | 09 Jan, 2024, 06:31: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by gargi.gholap | 26 Apr, 2019, 01:53: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by moshabankhan786 | 26 Apr, 2019, 11:08: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by amitnareliya5621 | 04 Mar, 2019, 04:09: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by Vidya | 10 Mar, 2018, 06:01: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by Topperlearning User | 31 Jul, 2014, 02:03: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by Topperlearning User | 31 Jul, 2014, 02:04: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by Topperlearning User | 31 Jul, 2014, 03:09: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by Topperlearning User | 31 Jul, 2014, 03:10: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by Topperlearning User | 31 Jul, 2014, 03:26: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×