CBSE Class 12-science Answered
using gauss's law derive an expression for electric field intensity long, straight line of linear charge density ø per cm.
Asked by Balan | 26 Mar, 2018, 01:39: PM
Expert Answer
Let us imagine a surface of cylinder symmetrically placed so that its axis coincides with the charged line as shown in figure. Let r be the radius of cylinder and l be its length. Very near to the charged line field lines are perpendicular to the charged line and no field lines are passing through the cross section of cylinder. There is a uniform electric field on the surface of cylinder.
As per Gauss law ...................(1)
Equation (1) can be written as E×2 π r×l = ( λ l ) / εo
Hence
Answered by Thiyagarajan K | 26 Mar, 2018, 08:43: PM
Concept Videos
CBSE 12-science - Physics
Asked by dasrituparna1999 | 13 Apr, 2024, 06:56: AM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by dasrituparna1999 | 12 Apr, 2024, 09:26: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by mishrigupta19319 | 08 Apr, 2024, 06:28: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by madhav9119887644 | 07 Apr, 2024, 08:10: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by mishrigupta19319 | 07 Apr, 2024, 11:23: AM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by adityagalar2007 | 06 Apr, 2024, 01:06: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by amlanmcob | 06 Apr, 2024, 12:27: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by hussain221man | 05 Apr, 2024, 08:44: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by mishrigupta19319 | 05 Apr, 2024, 12:01: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by manishamunda787 | 02 Apr, 2024, 11:07: AM
ANSWERED BY EXPERT