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# {urgent please}find perimeter \$ area of an isosceles right angel triangle each whose equal sides measure 20cm square take root 2 =2.144

Asked by Gaurav 20th July 2012, 4:02 PM
Answer : Gven : an issosceles right triangle whose equal sides measure 20 cm
To find : area and perimeter of that traingle

as we know that the area of right tringle = (1/2) * base * height
As we know the height = base = 20 cm
=> area= (1/2) *(20) *(20)
= 200 cm2 = 200m2 / (100 *100)  = 0.02 m2
The third side , b = underroot ( a2+a2)           { by right traingle property}
b= underoot(2* 202) = 20 * 2.144= 28.28 cm
therefore the perimeter = b+a+a = 28.28 +20+20
= 68.28 cm = 68.28 m / 100
= 0.6828 m
Answer : the perimeter = 0.6828m and area = 0.02 m2
Answered by Expert 22nd July 2012, 10:54 PM
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