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Under the same conditions of temperature and pressure samples of gases- H2, O2, N2, and CO2- contain the same number of molecules represented by N. If the molecules of H2 occupies V litres and has a mass of 2 gm. then: i) calculate the volume occupied by- 1) N molecules of CO2; 2) 3N mlecules of O2; 3)N/2 moleules of O2.
Asked by bdroy_2014 | 28 Jan, 2018, 03:07: PM
answered-by-expert Expert Answer
Mass space of space straight H subscript 2 space equals space 2 space gm 1 space mole space of space straight H subscript 2 space equals space 2 space gm space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 6.023 cross times 10 to the power of 23 space molecules space of space straight H subscript 2 space space space space space space space space space space space space space space space space therefore space straight N space equals space space 6.023 cross times 10 to the power of 23 space molecules As space Under space the space same space conditions space of space temperature space and space pressure space samples space of space gases space straight H subscript 2 comma space straight O subscript 2 comma space straight N subscript 2 comma space and space CO subscript 2 space contain space the space same space number space of space molecules open parentheses 1 close parentheses therefore space volume space occupied space by space straight N space molecules space of space CO subscript 2 space straight N space equals space space 6.023 cross times 10 to the power of 23 space molecules space space space space space equals space 1 space mole space space space space space space space space space space space equals space 22.4 space lit space space space space space space volume space occupied space by space straight N space molecules space of space CO subscript 2 space equals space 22.4 space lit open parentheses 2 close parentheses space Volume space occupied space by space 3 straight N space molecules space of space straight O subscript 2 space straight N space equals space space 6.023 cross times 10 to the power of 23 space molecules 3 straight N equals space 3 cross times space space 6.023 cross times 10 to the power of 23 space molecules space space space space space space equals space 3 cross times 22.4 space space space space space space space space space space space equals space 67.2 space lit space Volume space occupied space by space 3 straight N space molecules space of space straight O subscript 2 space equals space space 67.2 space lit open parentheses 3 close parentheses space Volume space occupied space by space straight N divided by 2 space space molecules space of space straight O subscript 2 space straight N space equals space space 6.023 cross times 10 to the power of 23 space molecules straight N over 2 equals space fraction numerator space 6.023 cross times 10 to the power of 23 over denominator 2 end fraction space space space space space space space equals space fraction numerator 22.4 over denominator 2 end fraction space space space space space space equals space 11.2 space lit Volume space occupied space by space straight N divided by 2 space space molecules space of space straight O subscript 2 space space equals space 11.2 space lit
Answered by Varsha | 29 Jan, 2018, 02:51: PM

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