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Home / Doubts and Solutions/JEE/Physics

Two thin rods of mass m and length l are arranged to form a cross the moment of inertia of the system aboit angular bisector is

Asked by jayasreetangirala28 14th April 2020, 8:08 PM
Answered by Expert
Answer:
T h e space m o m e n t space o f space i n e r t i a space o f space t h i n space r o d space o f space m a s s space m space a n d space l e n g t h space calligraphic l space i s comma space I equals space fraction numerator m calligraphic l squared over denominator 12 end fraction M o m e n t space o f space i n e r t i a comma space w h e n space t w o space r o d s space f o r m s space c r o s s space i s space I apostrophe space equals space 2 I space equals space fraction numerator 2 m calligraphic l squared over denominator 12 end fraction space M o m e n t space o f space i n e r t i a space o f space s y s t e m space a b o u t space t h e space a n g u l a r space b i s e c t o r space o f space r o d s space equals space fraction numerator I apostrophe over denominator 2 end fraction equals space fraction numerator m calligraphic l squared over denominator 12 end fraction  
Answered by Expert 14th April 2020, 8:48 PM
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