Two ships A and B are 10 km apart on north south. If A ship is due north of B,A travels towards east with velocity 5km/hr. ShipB travels due north with speed 5km/hr. Find the shortest distance between them
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Question:
Ship A is 10 km due west of ship B ship A is heading directly north at a speed of 30 kmph while ship B is heading in a direction 60 deg west of north at a speed of 20 kmph what will be their distance of closest approach?
Solution:
The figure below shows the velocity diagram of the two ships.
Here, r is the distance of closest approach.
From the figure, we get
Now, distance of closest approach is obtained when we put dr/dt = 0.
So, solving the above equation by substituting the values of vA and vB, we get ?
.
Substitute the value of t in equation of r to obtain distance of closest approach
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