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CBSE Class 10 Answered

Two resistance s when connected in parallel gives resultant value of 2ohm, when connected in series the value becomes 9ohm calculate the value of each resistance  
Asked by hdokang | 17 Aug, 2019, 10:34: PM
answered-by-expert Expert Answer
in series,  R1+R2 = 9 Ω    ...........................(1)
 
In parallel,   R1R2 /(R1+R2) = 2Ω  .......................(2)
 
from (1) and (2), we get, R1R2 = 18  ..............(3)
 
from (1) and (3), we have,  R1(9-R1) = 18  or  R12 - 9R1 + 18 = 0   or  (R1-6)(R1-3)=18 
 
Hence one resistor 6 Ω and other one 3 Ω
Answered by Thiyagarajan K | 17 Aug, 2019, 10:56: PM
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