CBSE Class 10 Answered
Two resistance s when connected in parallel gives resultant value of 2ohm, when connected in series the value becomes 9ohm calculate the value of each resistance
Asked by hdokang | 17 Aug, 2019, 10:34: PM
Expert Answer
in series, R1+R2 = 9 Ω ...........................(1)
In parallel, R1R2 /(R1+R2) = 2Ω .......................(2)
from (1) and (2), we get, R1R2 = 18 ..............(3)
from (1) and (3), we have, R1(9-R1) = 18 or R12 - 9R1 + 18 = 0 or (R1-6)(R1-3)=18
Hence one resistor 6 Ω and other one 3 Ω
Answered by Thiyagarajan K | 17 Aug, 2019, 10:56: PM
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