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Two positive point charges of 0.2 μC and 0.01 μC are placed 10 cm apart. Calculate the work done in reducing the distance to 5 cm.

Asked by Topperlearning User 22nd April 2015, 2:07 PM
Answered by Expert
Answer:

Given:

q1 = 0.2 μC 

q2 = 0.01 μC 

r= 10 cm = 0.1 m

r2 = 5 cm = 0.05

 

Work done in reducing the distance from 10 cm to 5 cm can be calculate by using the relation

  begin mathsize 11px style straight W space equals space fraction numerator straight q subscript 1 straight q subscript 2 over denominator 4 πε subscript 0 end fraction open square brackets 1 over straight r subscript 2 space minus space 1 over straight r subscript 1 close square brackets end style 

Answered by Expert 22nd April 2015, 4:07 PM
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