CBSE Class 11-science Answered
Two Pizzas one at 100 °C and another at 30 °C are kept on a table. Which one would cool off faster and by how many times? Temperature of surroundings is 20 °C.
Asked by Topperlearning User | 16 Apr, 2015, 09:27: AM
Expert Answer
Temperature T1 = 100 °C= 100 + 273 = 373 K
Temperature T2 = 30 °C = 30 + 273 = 303 K
Temperature of surroundings = 20 °C = 20 + 273 = 293 K
Using Stefan Boltzmann Law, we get
The pizza at 100 °C cools off 11.3 times faster than the pizza at 30 °C.
Answered by | 16 Apr, 2015, 11:27: AM
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