Two pendulums A and B of lengths 144 cm and 100 cm are initially in same phase at their equilibrium positions. After how many oscillations of B, they are in same phase again at equilibrium ?
Asked by dipanshusingla029
31st March 2018,
6:48 PM
Answered by Expert
Answer:
Time period of an oscillation 
, where L is length and g is acceleration due to gravity.
, where L is length and g is acceleration due to gravity.Since Period is prportional to square root of length, let us assume T = α
, where α is a constant
, where α is a constantHence period of A and B are 12α seconds and 10α seconds respectively.
To get the same phase after a given time, the clue is finding LCM of two periods which is 60α in this case.
hence in time 60α seconds, B will complete 6 oscillations. In this same time 60α seconds, oscillations made by A is (60α)/(12α) = 5.
Hence after 6 oscillations of B, A will be in same phase with B by completing 5 oscillations
Answered by Expert
1st April 2018,
8:16 AM
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