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Two particle are executing SHM of same amplitude A and freqency W along the X-axis . there mean position is separated by distance x ( x>A). If the max. separation between them is x+A , then what is the phase difference between their motion. And please explain what exactly is phase difference & ways to calculate it . thanks

Asked by sunakshi 22nd March 2014, 8:00 PM
Answered by Expert
Answer:
x subscript 1 equals A sin omega t x subscript 2 equals x subscript o plus A sin space left parenthesis omega t space plus space phi right parenthesis S e p a r a t i o n space equals space x subscript o plus A sin space left parenthesis omega t space plus space phi right parenthesis space minus space A sin omega t space space space space space space space space space space space space space space space space space space space space space space equals space x subscript o plus space 2 A space sin open parentheses ? over 2 close parentheses cos omega t M a x. space s e p a r a t i o n space equals space space x subscript o plus space 2 A space sin open parentheses ? over 2 close parentheses space equals space space x subscript o plus space A rightwards double arrow phi space equals space pi over 3
Answered by Expert 22nd March 2014, 8:28 PM
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