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Two linked genes a and b show 20% recombination.The individual of a dihybrid cross between   ++/++ x ab/ab shall show gametes: [I was not able to understand this question what examiner exactly wants to ask here, '++' signifies what ?SO,i request to the expert please explain this question in detail(also tell which concept should be used to answer this question)]                                                                              (a)++80:ab:20 (b)++50:ab:50 (c)++40:ab 40 : + a 10 : +b:10
Asked by Balbir | 30 Dec, 2019, 10:07: PM
answered-by-expert Expert Answer

As per the data, a and b show 20% recombination. This implies that there will be 20% crossing over and the progeny will be a recombination of both the parents.  
The percentage of linkage is 80%, so for both parents, there will be 40% and 40% chance of getting the progeny identical to the two parents.

The combined linkage frequency between the parental combinations ++ and ab is 80%

Since, the combined recombination frequency between the recombinant combination +a and +b is 20%, the individual frequencies would be half of the combined.

So, the correct option is ' ++ 40 : ab 40 : + a 10 : + b 10.

Answered by Sheetal Kolte | 02 Jan, 2020, 11:47: AM

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