Contact

For Study plan details

10:00 AM to 7:00 PM IST all days.

For Franchisee Enquiry

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

93219 24448 / 99871 78554

Mon to Sat - 10 AM to 7 PM

# Two large glass plate are placed vertically and parallel to each other inside a tank of water with separation between the plate is equals to 1 mm .Find the rise of water in the space between the plates surface tension of water equals 0.075 Nm^-1

Asked by Harshjaiswal9450 27th April 2020, 12:26 PM
Surface tension force is acting along the length l on both the plates.

Hence surface tension force = T × 2 l

surface tension force is balanced by weight of liquid column,  l×h×d×ρ

where h is rise of water column, d is distance between plates and ρ is density

Hence we have,  T × 2 l = l×h×d×ρ×g

h = 2T / ( d×ρ×g )  = ( 2 × 0.075 ) / ( 1 × 10-3 × 1000×9.8 ) = 0.0153 m  ≈ 15 mm
Answered by Expert 27th April 2020, 2:43 PM
• 1
• 2
• 3
• 4
• 5
• 6
• 7
• 8
• 9
• 10

You have rated this answer /10

RELATED STUDY RESOURCES :

### Latest Questions

CBSE X Biology
Asked by Sureshgowdayd548 28th October 2020, 10:50 PM
CBSE X Biology
Asked by reenacharan2008 28th October 2020, 9:11 PM