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Two equal charges are placed at a separation  of 1.0 m. what should be the magnitude of the charges so that the force between them euals weight of a 50 kg person?

Asked by haroonrashidgkp 19th April 2018, 8:47 PM
Answered by Expert
Answer:
Force F = (q2) / [ (4πε0) r2 ]; q = 1 C , F = 50×9.8 N , ε0 = 8.85 × 10-12 F/m
 
Separation distance r = [ 1012 / (4π×8.85×50×9.8) ]1/2 = 4283 m
Answered by Expert 19th April 2018, 10:55 PM
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