two cars, P and Q start side by side from rest at the same instant and in the same direction. P accelerates uniformly at 4 metre per sec square for 10 sec and then moves with uniform velocity. Q moves with uniform acceleration of 3 metre per sec square. find the distance between them 30 seconds after start. which one is ahead and why?
Asked by shreeyarokade
1st April 2018,
11:05 AM
Answered by Expert
Answer:
Movement of P:-
First 10 seconds accelerated motion with acceleration 4 m / s2 ; hence S1 = (1/2)×4×10×10 = 200 m
speed after 10 seconds v = 4×10 = 40 m/s
distance travelled next 20 seconds S2 = 40×20 = 800 m/s
total distance travelled in 30 seconds = S1+S2 = 200+800 = 1000 m
Movement of Q:
Distance travelled in 30 seconds S = (1/2)×3×30×30 = 1350 m
Hence Q is ahead of by 350 m
Answered by Expert
1st April 2018,
12:14 PM
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