Two capacitors of capacitance C and 2C are joined in parallel and charged to a potential v.The battery is then disconnected and the capacitor of capacity C is filled with a dielectric medium of constant K.The potential capacitor across the capacitor will be
Asked by sandhyamsani
15th May 2017,
4:49 PM
Answered by Expert
Answer:
The original capacitance of the parallel combination of C and 2 C is = C +2C = 3C
Total charge Q = 3CV
When the capacitor C is filled with a dielectric, its capacitance becomes KC.
Therefore, after the capacitor is filled with dielectric the capacitance of the combination, C' = KC + 2C = C (K + 2).
However, the charge remains the same, i.e. Q = 3CV
Therefore, the potential difference across the capacitors will be
Answered by Expert
15th May 2017,
6:14 PM
Rate this answer
- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10
You have rated this answer 10/10
Your answer has been posted successfully!
RELATED STUDY RESOURCES :
Browse free questions and answers by Chapters
- 1 Thermodynamics
- 2 Gravitation
- 3 Electromagnetic Waves
- 4 Communication Systems
- 5 Laws of Motion
- 6 Current Electricity
- 7 Work, Energy and Power
- 8 Kinematics
- 9 Physics and Measurement
- 10 Rotational Motion
- 11 Properties of Solids and Liquids
- 12 Kinetic Theory of Gases
- 13 Oscillations and Waves
- 14 Electrostatics
- 15 Magnetic Effects of Current and Magnetism
- 16 Electromagnetic Induction and Alternating Currents
- 17 Optics
- 18 Dual Nature of Matter and Radiation
- 19 Atoms and Nuclei
- 20 Electronic Devices
Trending Tags
Latest Questions
JEE Main Mathematics
Asked by amaladelsingh
28th October 2020,
10:24 PM
CBSE X Biology
Asked by reenacharan2008
28th October 2020,
9:11 PM
