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Two capacitors of capacitance C and 2C are joined in parallel and charged to a potential v.The battery is then disconnected and the capacitor of capacity C is filled with a dielectric medium of constant K.The potential capacitor across the capacitor will be 

Asked by sandhyamsani 15th May 2017, 4:49 PM
Answered by Expert
Answer:
The original capacitance of the parallel combination of C and 2 C is = C +2C = 3C
Total charge Q = 3CV
When the capacitor C is filled with a dielectric, its capacitance becomes KC. 
Therefore, after the capacitor is filled with dielectric the capacitance of the combination, C' = KC + 2C = C (K + 2).
However, the charge remains the same, i.e. Q = 3CV
Therefore, the potential difference across the capacitors will be 
begin mathsize 12px style fraction numerator Q over denominator C apostrophe end fraction equals fraction numerator 3 C V over denominator open parentheses K space plus space 2 close parentheses begin display style C end style end fraction
therefore fraction numerator begin display style Q end style over denominator begin display style C apostrophe end style end fraction equals fraction numerator begin display style 3 V end style over denominator begin display style open parentheses K space plus space 2 close parentheses end style end fraction end style
Answered by Expert 15th May 2017, 6:14 PM
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