Contact

For Study plan details

10:00 AM to 7:00 PM IST all days.

Franchisee/Partner Enquiry (South)

Franchisee/Partner Enquiry (North, West & East)

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

9372462318 / 9987178554

Mon to Sat - 10 AM to 7 PM

# Two capacitors of capacitance C and 2C are joined in parallel and charged to a potential v.The battery is then disconnected and the capacitor of capacity C is filled with a dielectric medium of constant K.The potential capacitor across the capacitor will be

Asked by sandhyamsani 15th May 2017, 4:49 PM
The original capacitance of the parallel combination of C and 2 C is = C +2C = 3C
Total charge Q = 3CV
When the capacitor C is filled with a dielectric, its capacitance becomes KC.
Therefore, after the capacitor is filled with dielectric the capacitance of the combination, C' = KC + 2C = C (K + 2).
However, the charge remains the same, i.e. Q = 3CV
Therefore, the potential difference across the capacitors will be
Answered by Expert 15th May 2017, 6:14 PM
• 1
• 2
• 3
• 4
• 5
• 6
• 7
• 8
• 9
• 10

You have rated this answer 10/10

### Free related questions

RELATED STUDY RESOURCES :