two bodies of mass 1kg and 2kg are attached to the ends of a 2m long weight less rod. this system is rotating about an axis passing through middle point of rod. calculate moment of inertia of system
Asked by vvelesha
29th August 2018,
8:40 PM
Answered by Expert
Answer:
Let two masses m1 and m2 are connected by a light rod and this rod is revolving around an axis passing
through middle of the rod as shown in figure. Let r1 and r2 are the respective distance from the mid point O.
Moment of inertia of this configuration = m1×r12 + m2×r22
In the given question, m1 = 1 kg , m2 = 2 kg, r1 = r2 = 1 m
Moment of inertia = 1×12 + 2×12 = 3 kg-m2
Answered by Expert
31st August 2018,
12:07 AM
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