Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

Trigonometry.

Asked by khushal305 28th September 2009, 1:48 PM
Answered by Expert
Answer:

xcos θ/a +ysin θ/b = 1

xsin θ/a - ycos θ/b = 1

Squaring and adding,

x2cos2 θ/a2 +2(xcos θ/a)(ysin θ/b) + y2sin2 θ/b2 + x2sin2 θ/a2 - 2(xsin θ/a)(ycos θ/b) + y2cos2 θ/b2 = 2

x2(cos2 θ + sin2 θ)/a2 + y2(sin2 θ +cos2 θ)/b2 = 2

x2/a2 + y2/b2 = 2

Regards,

Team,

TopperLearning.

 

Answered by Expert 28th September 2009, 5:32 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp