CBSE Class 10 Answered
Trigonometry.
Asked by khushal305 | 28 Sep, 2009, 01:48: PM
Expert Answer
xcos θ/a +ysin θ/b = 1
xsin θ/a - ycos θ/b = 1
Squaring and adding,
x2cos2 θ/a2 +2(xcos θ/a)(ysin θ/b) + y2sin2 θ/b2 + x2sin2 θ/a2 - 2(xsin θ/a)(ycos θ/b) + y2cos2 θ/b2 = 2
x2(cos2 θ + sin2 θ)/a2 + y2(sin2 θ +cos2 θ)/b2 = 2
x2/a2 + y2/b2 = 2
Regards,
Team,
TopperLearning.
Answered by | 28 Sep, 2009, 05:32: PM
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