Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days
8104911739
For Business Enquiry

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

trigonometric problem

Asked by 30th August 2008, 4:50 PM
Answered by Expert
Answer:

we know that tanx = 2 tan x/2 / (1-tan2 x/2)

also cos2x = cos2x-sin2x = (cos2x-sin2x) / (cos2x+sin2x) = (1-tan2x)  / (1+tan2x)

so 1+ tanx tan x/2 = 1 + 2tan2 x/2 / (1-tan2 x/2) = (1+tan2x/2)  / (1-tan2x/2) = 1/cos x = sec x

similarly tanx cot x/2 -1 = -1 + 2 / (1-tan2 x/2) = (1+tan2x/2)  / (1-tan2x/2) = 1/cos x = sec x

Answered by Expert 12th September 2008, 3:48 AM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Free related questions

CBSE QUESTION ANSWERS

Browse free questions and answers by Chapters

Chat with us on WhatsApp