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CBSE - X - Mathematics

trignomentry

Asked by 12th February 2009, 9:12 PM
Answered by Expert

Answer:

put cotA and sinA in terms of sinA and cosA

on solving by taking lcm we get

cos3A - sin3A / sinA cosA (cosA - sinA)

=(cosA - sinA ) (cos2A + sin2A +sinA cosA) / sinA cosA (cosA - sinA)

=(cos2A + sin2A +sinA cosA) / sinA cosA

=cotA + tanA +1

Answered by Expert 16th February 2009, 9:14 PM

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